Hace tiempo que tendría que haber escrito sobre las charadas (riddles) the Howard Oakley, una de las cosas que más me gustan de su siempre interesante blog The Eclectic Light Company.
Lo más curioso es que lleva desde el 29 de Junio de 2019 publicándolas sin saltárselas ni una sola semana… pero no tiene forma de encontrar esas charadas de los sábados — y las soluciones de los lunes — de forma sencilla.
Así que me puse a escribir un script en Python que me proporciona el URL de cualquier charada, o su solución, asumiendo que se sigan publicando de forma ininterrumpida.
Aquí lo tenéis, por si os sirve de algo (con sus comentarios):
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| #!/usr/bin/env python | |
| import datetime as dt | |
| def riddle_for_date(date, solutions=False): | |
| """ | |
| Determines the number for the Saturday Mac Riddle associated with | |
| a given date, considering whether it is the date for the riddle | |
| or the solutions. | |
| Parameters: | |
| date (datetime): The date for which to determine the riddle number. | |
| solutions (bool): Indicates whether to consider the date for | |
| solutions (True) or the riddle itself (False). Default is False. | |
| Returns: | |
| int: The riddle number associated with the specified date. | |
| Raises: | |
| None | |
| """ | |
| base_date = dt.datetime(2019,6,29) # Date of first riddle | |
| if solutions: # A monday | |
| # We provide the date for the first solution by offsetting | |
| # by two days (from Saturday to Monday) | |
| base_date = base_date+dt.timedelta(days=2) | |
| return ((date-base_date).days//7 + 1) | |
| def date_for_riddle(riddle_num, solutions=True): | |
| """ | |
| Computes the date associated with a given Eclectic Light Co | |
| Saturday's riddle number, considering whether to give the date for | |
| the riddle or for the solution. | |
| Parameters: | |
| riddle_num (int): The number of the riddle for which to calculate | |
| the date. | |
| solutions (bool): Indicates whether to use the solution's or the | |
| riddle's date. Default is True (for the solution's date). | |
| Returns: | |
| datetime: Computed date associated with the specified riddle. | |
| Raises: | |
| ValueError: If the specified riddle number is less than 1. | |
| """ | |
| # Set a base date for the riddles | |
| # The first riddle was issued on June 29th, 2019 | |
| base_date = dt.datetime(2019, 6, 29) | |
| # Offset base date to the next Monday (two days after) | |
| # if solutions are requested | |
| if solutions: | |
| base_date = base_date + dt.timedelta(days=2) | |
| # Validate riddle number | |
| riddle_num = int(riddle_num) | |
| # We use -1 to indicate the latest date | |
| if riddle_num < 1 and riddle_num != -1: | |
| raise ValueError(f"The specified riddle number ({riddle_num}) is less than 1, and not -1.") | |
| # Compute the date associated with the riddle number | |
| # by adding as many weeks as the riddle number – 1. | |
| if riddle_num == -1: # Latest riddle | |
| riddle_num = riddle_for_date( | |
| dt.datetime.today(), | |
| solutions=solutions | |
| ) | |
| result = base_date + (riddle_num – 1) * dt.timedelta(days=7) | |
| return result | |
| def url_for_riddle(riddle_num, solutions=True, open_in_browser=False): | |
| """ | |
| Generates a URL for accessing a specific Mac riddle from | |
| the Eclectic Light Company's blog https://eclecticlight.co/. | |
| Parameters: | |
| riddle_num (int): The number of the riddle to generate URL for. | |
| solutions (bool): Indicates whether the URL should lead to the | |
| riddle's solutions (True), or just to the | |
| original riddle. Default is True. | |
| open_in_browser (bool): Indicates whether the generated URL should | |
| be opened in the default web browser. | |
| Default is False. | |
| Returns: | |
| str: The generated URL for the specified Mac riddle. | |
| Raises: | |
| ValueError (through `date_for_riddle`) if the riddle_num is less | |
| than 1, or not an int. | |
| """ | |
| if riddle_num == -1: | |
| riddle_num = riddle_for_date( | |
| dt.datetime.now(), | |
| solutions=solutions | |
| ) | |
| date = date_for_riddle(riddle_num,solutions=solutions) | |
| slug = f"saturday-mac-riddles-{riddle_num}/" | |
| if solutions: | |
| slug = f"solutions-to-{slug}" | |
| result = f"https://eclecticlight.co/{date.year:04d}/{date.month:02d}/{date.day:02}/{slug}" | |
| if open_in_browser: | |
| import webbrowser | |
| webbrowser.open(result) | |
| return result | |
| if __name__ == "__main__": | |
| """ | |
| Main: | |
| Print URLs, and open in webbrowser the several IDs. | |
| It should raise an exception while trying to open riddle 0. | |
| """ | |
| print(f"Opening URL: {url_for_riddle( -1, solutions=False, open_in_browser=True)}") | |
| print(f"Opening URL: {url_for_riddle( -1, solutions=True, open_in_browser=True)}") | |
| print(f"Opening URL: {url_for_riddle( 123, solutions=False, open_in_browser=True)}") | |
| print(f"Opening URL: {url_for_riddle( 123, solutions=True, open_in_browser=True)}") | |
| print(f"Opening URL: {url_for_riddle(1234, solutions=False, open_in_browser=True)}") | |
| print(f"Opening URL: {url_for_riddle(1234, solutions=True, open_in_browser=True)}") | |
| print(f"Opening URL: {url_for_riddle( 0, solutions=False, open_in_browser=True)}") | |
| print(f"Opening URL: {url_for_riddle( 0, solutions=True, open_in_browser=True)}") |
Perdón por haberlo escrito en inglés, pero dado que el sitio de Howard Oakley está en inglés, lo preferí. Con ese código en Python, ahora podéis teclear algo como:
url_for_riddle(-1,True,True)Y se abrirá en vuestro navegador por defecto las soluciones a la última charada de Howard Oakley.
Comentarios
2 respuestas a «The Eclectic Light Company y las charadas de Howard Oakley»
@juandesant@juandesant.wpcomstaging.com probando si este comentario acaba en el blog…
Sip, y este acabará en el Fediverso…